(1/2)^2x-12/2^x+32=0

Solution for (1/2)^2x-12/2^x+32=0 equation:

(1/2)^2x-12/2^x+32=0


Domain of the equation: 2)^2x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2^x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)^2x-12/2^x+32=0

We calculate fractions


((+1*2^x)/2^2x*2^x)+(-24x)/2^2x*2^x)+32=0


We calculate terms in parentheses: +((+1*2^x)/2^2x*2^x), so:

(+1*2^x)/2^2x*2^x

We multiply all the terms by the denominator


(+1*2^x)

We get rid of parentheses

1*2^x

Wy multiply elements

2x

Back to the equation:

+(2x)


We multiply all the terms by the denominator


2x*2^2x*2^x)+32+(-24x)=0

Wy multiply elements

8x^4*2-24x)=0

We do not support expression: x^4